Answer:

No — array indexes start at zero, and go up to length-1.

IndexOutOfBoundsException

Here is a program that asks the user for an integer and for an array index where it is to be placed. Only indexes 0 through 9 are allowed. Any other index causes an IndexOutOfBoundsException.

import java.util.* ;

public class IndexPractice
{
  public static void main ( String[] a )
  {
    Scanner scan = new Scanner( System.in );
    int data=0, slot=0 ;
    int[] value = new int[10];

    try
    { 
      System.out.print("Enter the data: ");
      data = scan.nextInt();
      System.out.print("Enter the array index: ");
      slot = scan.nextInt();
      value[slot] = data;
    }

    catch (InputMismatchException ex )
    {  
      System.out.println("This is your problem: " +  ex.getMessage()   
          + "\nHere is where it happened:\n");
       ex.printStackTrace();  
    } 

    catch (IndexOutOfBoundsException ex )
    {  
       System.out.println("This is your problem: " +  ex.getMessage()   
          + "\nHere is where it happened:\n");
       ex.printStackTrace(); 
     } 

    System.out.println("Good-by" );
  }
}

 

QUESTION 3:

If the user enters:

Enter the data: 8
Enter the array index: 10
will an exception be thrown?